B. Solve the problem: Mrs. Reyna is planning to fence her vacant lot for a parking space. The desired length of the lot is 6 m longer than its width. What will be the possible dimensions of the rectangular parking space if it should be less than 40m2?
(Hint: length x width = Area of rectangle)

Step-by-step explanation:

Given

Area of the rectangle =Length × width

Given

The desired length of the lot is 6 m longer than its width, then L = 6+W

A = LW

40 = (6+W)W

40= 6W+W²

W²+6W -40 = 0

W²+10W-4W-40 = 0

W(w+10)-4(w+10) = 0

W+10 = 0 and w-4 = 4

W = -10 and w = 4

Width can't be negative

W = 4m

Since L = 6+w

L = 6+4

L = 10m

Hence the possible dimension s 4m by 10m

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

include a picture of the drawing in order for me to

step-by-step explanation: