Are the triangles below congruent by Side-Side-Side, Side-Angle-Side, or neither?

C

Step-by-step explanation:

Lets see what we have,

So far we have a side and an angle congruent.

But wait, if two lines intersect, the angle of intersection between the two are equal meaning we have a second angle, and we know now as a result the third angle is 180 minus the two known angles

This means its a Side Angle Angle, however neither of these show this so C

Hope this helps :)

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.