Question 5 (1 point) At the corner produce market, apples cost $2 each and
oranges cost $1 each.
Find the cost of:
a. 6 apples and 3 oranges:$
apples &
oranges
b. 4 apples and 4 oranges:$
apples &
oranges
c. 5 apples and 4 oranges:
apples &
oranges
d. 8 apples and 2 oranges:$ apples &
oranges
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Answer/Step-by-step explanation:

Unit cost of apple = $2 let each

Unit cost of orange = $1 per each

a. Cost of 6 apples = 6 × $2 = $12

Cost of 3 oranges = 3 × $1 = $3

b. Cost of 4 apples = 4 × $2 = $8

Cost of 4 oranges = 4 × $1 = $4

c. Cost of 5 apples = 5 × $2 = $10

Cost of 4 oranges = 4 × $1 = $4

d. Cost of 8 apples = 8 × $2 = $16

Cost of 2 oranges = 2 × $1 = $2

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet