Please help 15 points available! What is the equation of the line that is perpendicular to y - 3 x = 2 and that passes through (6,1)? y = 1/3x - 1
y = 1/3x + 3
y = -1/3x + 3
y = -1/3x - 1

C) y = -1/3x + 3

Step-by-step explanation:

y - 3x = 2

  + 3x   + 3x

y = 3x + 2

find the reciprocal of the slope (3) which is -1/3 so -1/3 will be the slope for the perpendicular line

y = (-1/3)x + b

now find the y-intercept (b)

(6,1) x = 6   y = 1

y = (-1/3)x + b

1 = (-1/3)6 + b

1 = -2 + b

+2  +2

3 = b

y = (-1/3)x + 3

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step-by-step explanation:

a

step-by-step explanation: