Mathematics, 12.11.2020 23:20, naimareiad

consider this polynomial equation 6(x-3)(x^2+4)(x+1)=0 the equation has ( A. 2 B.3 C.4) solutions. it's real solutions are x = (-2 -1 and 2 or. -1 and 3)

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consider this polynomial equation 6(x-3)(x^2+4)(x+1)=0 the equation has ( A. 2 B.3 C.4) solutions. i...