Alex purchased 1 adult ticket and 2 student tickets for a total of $22. Jen purchased 1 adult ticket and 3 student tickets for a total of $28.
Let a = cost of adult ticket
Let s = cost of student ticket
Write the two equations which could be used to solve this problem using
elimination.

C. a + 2s = $22

a + 3s = $28

Step-by-step explanation:

a = cost of adult ticket

s = cost of student ticket

✍️Cost of adult tickets purchased by Alex = 1 * a = a

Cost of 2 students tickets purchased by Alex = 2 * s = 2s

Total cost of total ticket purchased by Alex = $22

Therefore, equation for Alex would be:

✅a + 2s = $22

✍️Cost of adult tickets purchased by Jen = 1 * a = a

Cost of 3 students tickets purchased by Alex = 3 * s = 3s

Total cost of total ticket purchased by Alex = $28

Therefore, equation for Jen would be:

✅a + 3s = $28

✍️The answer would be option C:

a + 2s = $22

a + 3s = $28

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6