Sam computed a 95% confidence interval for μ from a specific random sample. His confidence interval was 10.1 < μ < 12.2. He claims that the probability that μ is in this interval is 0.95. What is wrong with his claim? A) Either μ is in the interval or it is not. Therefore, the probability that μ is in this interval is 0.95 or 0.05.
B) A probability can not be assigned to the event of μ falling in this interval.
C) Either μ is in the interval or it is not. Therefore, the probability that μ is in this interval is 0 or 1.
D) The probability that μ is in this interval is 0.05.

C) Either μ is in the interval or it is not. Therefore, the probability that μ is in this interval is 0 or 1.

Step-by-step explanation: A 95% Confidence interval shows that there is a 95% confidence that the true parameter is between the lower and upper limits.

A CI is not a probability that the true parameter is in between the interval. The true parameter is either in the interval or not.

So, probability of falling between the limits is 0 (no chance of being in this interval) or 1 (100% possibility of being in this interval).

Then, "either μ is in the interval or it is not. therefore, the probability that μ is in this interval is 0 or 1." is correct.

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse