A landlord owns 3 condominiums, a l-bedroom condo, a 2-bedroom condo, and a 3- bedroom condo. The total rent she receives is $1240. She needs to make repairs on the

condos, and it costs 10% of the 1-bedroom condo's rent for its repairs, 20% of the 2-

bedroom for its repairs, and 30% of the 3-bedroom condo's rent for its repairs. The total

repair bill was $276. The 3-bedroom condo's rent is twice the 1-bedroom condo's rent.

How much is the rent for all three condos? Define your variables then write and solve a

system of equations.

1 bedroom = $280

2 bedroom = $400

3 bedroom = $560

Step-by-step explanation:

Given that :

Total rent received = 1240

Rent amount of 3 bedroom = 2 times rent of 1 bedroom

Let 1 bedroom = x

2 bedroom = y

3 bedroom = 2x

x + y + 2x = 1240

3x + y = 1240 ---(1)

Repair cost :

10% of x = 0.1x

20% of y = 0.2y

30% of 2x = 0.6x

0.1x + 0.2y + 0.6x = 276

0.7x + 0.2y = 276 - - - (2)

From (1)

y = 1240 - 3x

0.7x + 0.2(1240 - 3x) = 276

0.7x + 248 - 0.6x = 276

0.1x + 248 = 276

0.1x = 28

x = $280

1 bedroom = $280

3 bedroom = $280 * 2 = $560

2 bedroom = $1240 - $840 = $400

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !