Let's solve 5\cdot 2^x=2405⋅2
Let's solve 5\cdot 2^x=2405⋅2 x
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned}
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x =240
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x =240=48
Let's solve 5\cdot 2^x=2405⋅2 x =2405, dot, 2, start superscript, x, end superscript, equals, 240.To solve for xxx, we must first isolate the exponential part. To do this, divide both sides by 555 as shown below. We do not multiply the 555 and the 222 as this goes against the order of operations!\begin{aligned} 5\cdot 2^x&=240 2^x&=48 \end{aligned} 5⋅2 x 2 x =240=48