Using the table, give the percentage associated with each unit of standard deviation in the standard normal curve to the nearest hundredth.
Area, A(x)
Area, A(x)
0.4953
0.2 0.0793
0.4 0.1554
0.6 0.2257
0.8
0.2881
1.0 0.3413
1.2 0.3849
1.4 0.4192
1.6 0.4452
1.8 0.4641
2.0 0.4772
2.2 0.4861
2.4 0.4918
2.6
2.8 0.4974
3.0 0.4987
3.2 0.4993
3.4 0.4997
3.6 0.4998
3.8 0.4999
4.0 0.5000
Standard Deviation Percentage Area
-1 to O
%
O to +1
%
O to +2
O to +3
%
-1 to +2

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

i suppose it should be (y=2x-5)

step-by-step explanation:

54/3 is 18 so 18 is your answer