Consider function f. f(x)= x^3 + 2x^2 - 5x - 6

Select the locations of the zeros of function f on the coordinate plane. Then select the end behavior of its graph.

x = 2, x = -1, x = -3As x approaches negative infinity, f(x) approaches negative infinity

Step-by-step explanation:

Given function

f(x)= x^3 + 2x^2 - 5x - 6

Finding zero's

x^3 + 2x^2 - 5x - 6 = 0x^3 - 2x^2 + 4x^2 - 8x +3x - 6 =(x - 2)(x^2 + 4x + 3) = (x - 2)(x^2 + x + 3x + 3) = (x - 2)(x(x + 1) + 3(x + 3)) =(x - 2)(x + 1)(x + 3)

Zero's are

x = 2, x = -1, x = -3

See the graph attached

Correct end behavior as per graph:

As x approaches negative infinity, f(x) approaches negative infinity

Idrk but i think u should figure out the n dia n then the units it will make it way more easier

Ibelieve the answer is b. y=0 would make the line horizontal across the x.