Let the factors, a1, a2, … a9 of a9 be written in a square 3 by 3 array as indicated. Let a1 Help me plz

61.2

Step-by-step explanation:

To solve this, we would have to use the arithmetic progression formula

S(n) = a + (n - 1) d, where

S(n) = is the value of the nth term

a = value of the first term

n = the nth term we're interested in

d = difference between successive terms

We're given that the first term, a1 = 1.we also know that the 6th term, a6 = 44

If so, we can use this to get our "d", saying

44 = 1 + (6 - 1) d

where

44 is the value of the 6th term, and n is 6. Also, the first term a = 1. Simplifying further we have

44 = 1 + 5d

5d = 44 - 1

5d = 43

d = 43/5

d = 8.6

This means that the difference between successive term is 8.6, we then use this "d" to find our 8th term

S(n) = 1 + (8 - 1) 8.6

S(n) = 1 + 7 * 8.6

S(n) = 1 + 60.2

S(n) = 61.2

Therefore, the 8th term is 61.2

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

-2

7 - 9 = -2

reversed:

-2 + 9 = 7