Orchestra Tonight is selling tickets for its local performance. Orchestra fans can buy tickets to sit in the balcony or on the floor of the concert hall. Tickets for floor seats are $83 each. Tickets for the balcony are 60% of the price of the floor tickets. Which inequality represents all possible combinations of f, the number of tickets for floor seats, and b, the number of tickets for balcony seats, that a person can buy and spend no more than $560?

Step-by-step explanation:

Given that the cost of 1 floor ticket = $ 83.

Cost for f floor tickets = $ 83f

Ticket for 1 balcony ticket = 60% of floor ticket.

= 0.60 x 83 = $49.8

Cost for b balcony tickets = $ 49.8b.

Total cost for f floor tickets and b balcony tickets, C= 83f+49.8b.

As the person can spend a maximum of $560,

So,

.

Hence, the required inequality is .

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

what are you doing do you need examples of variable questions?

step-by-step explanation:

5a-1=9               bring the one over the =

5a=10                     divide by your variable

a=2

brainliest? ?

here try this one

3a-24=0