In your marble collection, 4/7 of the marbles are blue and 4/21 of the marbles are red. how many times more blue marbles do you have than red marbles?

3 times.

Step-by-step explanation:

We begin by knowing that 4/7 is greater than 4/21. So you should know how many times there are more blue marbles than red marbles. That's,

Let X = number of times there are more blue marbles than red marbles

4/7 = X * 4/21

Isolating X,

X = 4/7 ÷ 4/21

That's,  

Then there are three times more blue marbles than red marbles.

It can be easily demonstrated, by substituting X in the original equation, or multiplying 3 by 4/21

4/7 = X * 4/21

4/7 = 3 * 4/21

4/7 = 12/21

4/7 = 12/3 / 21/3

4/7 = 4/7

Hope this helps!

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

step-by-step explanation:

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