Instead of handing out candy like a well-adjusted person on Halloween, grumpy, anti-social Professor Sosa decides to stand on top of a 400 ft building and toss candy treats onto the ground below. If he drops a bag of candy corn, how long will it take for it to land on the ground? What will the velocity of the bag be when it hits the ground?

The bag of candy corn will take 5 seconds to land on the floor and it will hit it with velocity of 49m/s.

Step-by-step explanation: A free falling object has only Gravitational Force acting on it, so acceleration will be due to gravity, which has magnitude

g = 9.8m/s².

As Professor Sosa drops the bag, its initial velocity and time are 0.

The building has a height of 400ft, so adjusting units: y = 121.92 m and = 0.

For this problem, going down will be the positive reference.

Then:

t ≈ 5

It will take 5s for the candy corn bag to land on the ground.

Acceleration is the change in velocity per change in time, so:

As initial velocity and time are 0 and rearraging it:

v = g.t

v = 9.8*5

v = 49

The bag will hit the ground with velocity of magnitude 49 m/s.

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

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step-by-step explanation: