At time t minutes, the position of a body moving along the s-axis is s= t cubed - 27t squared + 200t feet. a. Find the body's acceleration each time the velocity is zero.

Step-by-step explanation:

Given the expression for the position of a body moving along the s-axis expressed as;

The acceleration of the body function will be gotten by finding the second derivative of the displacement function as shown;

First we need to get the time taken when the velocity is zero.

factorize;

t = 54±√54²-4(3)(200)/2(3)

t = 54±√2916-2400/2(3)

t = 54±√516/6

t = 54±22.72/6

t = 54+22.72/6 and 54-22.72/6

t = 12.79s and t = 5.21s

Get the acceleration;

at t = 12.79

a = 6t-54

a = 6(12.79)-54

a = 76.74-54

a = 22.74m/s²

at t = 5.21

a = 6t-54

a = 6(5.21)-54

a = 31.26-54

a = -22.74m/s²

Hence the body's acceleration each time the velocity is zero are 22.74m/s² and -22.74m/s²

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: