Mathematics, 11.11.2020 14:00, mrylenastewart

What is the equation of the line that passes through the point (8,4) and has a slope of 3/2 ?

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answered: allanarayos5597

The equation of a line that has a slope of 3/2 and passes through (8, 4) can be written as:

$y - 4 = \frac{3}{2} (x - 8)$ (point-slope form) or

$y = \frac{3}{2}x - 8$ (slope-intercept form).

Given:

a point on a line: (8, 4)

slope of the line: 3/2

The equation of the line can be written in either point-slope form or slope-intercept form.

First, let's write the equation in point-slope form since we know one of the points and the slope.

Point-slope equation takes the form: y - b = m(x - a)

Where,

(8, 4) = (a, b), andm = 3/2Substitute

$y - 4 = \frac{3}{2} (x - 8)$ =>> point-slope form.

Also, we can rewrite in slope-intercept form as follows:

$y - 4 = \frac{3}{2} (x - 8)$

Open bracket

$y - 4 = \frac{3}{2}x - 12$

Add 4 to both sides

$y - 4 + 4 = \frac{3}{2}x - 12 + 4\\\\y = \frac{3}{2}x - 8$ (slope-intercept form)

Therefore, the equation of a line that has a slope of 3/2 and passes through (8, 4) can be written as:

$y - 4 = \frac{3}{2} (x - 8)$ (point-slope form) or

$y = \frac{3}{2}x - 8$ (slope-intercept form).

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answered: bigblow

y = $\frac{3}{2}$ x - 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = $\frac{3}{2}$ , thus

y = $\frac{3}{2}$ x + c ← is the partial equation

To find c substitute (8, 4) into the partial equation

4 = 12 + c ⇒ c = 4 - 12 = - 8

y = $\frac{3}{2}$ x - 8 ← equation of line

answered: Guest

the highest percentage for deaths in construction from highest to lowest is as follows: falls, struck by objects, electrocution, and caught-in/between. these four are collectively known as fatal four.

in the case of falls, the type that is responsible for the overall highest death in the category is falls from roofs.

answered: Guest

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180

same as (2x + 16) + (x) = 180

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