what is the equation of a line in slope intercept form that is perpendicular to y=2x+2 and passes through the point (8,-4)

The equation of the line that is perpendicular to y = 2x + 2 is

y = -1/2x

Step-by-step explanation:

The original equation is y = 2x + 2; it's slope is 2

Any line perpendicular to this equation would have to have a slope that is the negative reciprocal of the original slope.

Example:

y = 2x + 2 so,

the perpendicular line's slope must be -1/2

Write a new equation with the new slope:

y = -1/2x + b

We know that this line passes through (8, -4)

Plug these coordinates in the equation to find b, the y-intercept

-4 = -1/2 (8) + b

-4 = -4 + b

0 = b

b = 0

We do not have to write y = -1/2x + 0

So, our final answer is "y = -1/2x  is perpendicular to y = 2x+2"

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