The points (-1, r) and (2, 1) lie on a line with slope 2. Find the missing coordinate r Please help!!!

r = -5

Step-by-step explanation:

Slope = (y2 - y1)/(x2 - x1)

(-1, r)

(2, 1)

r - 1/-1 - 2 = r - 1/-3

Slope = 2

-3 x 2 = -6

-6 -(-1) = -5

-5 - 1 = -6

-6/-3 = 2

So:

r = -5

Hope this helps!

9514 1404 393

  r = -5

Step-by-step explanation:

The x-coordinate of the partially-defined point is 3 units less than the x-coordinate of the given point. The slope of 2 tells you the y-coordinate of the partial point (r) will be 2·3 = 6 units less than the y-coordinate of the given point. That is ...

  r = 1 - 2·3

  r = -5

__

You are given the slope of the line and a point on it, so you can write the point-slope equation of the line:

  y -y1 = m(x -x1) . . . . . . . line with slope m through point (x1, y1).

For the given point and slope, this is ...

  y -1 = 2(x -2)

For an x-value of -1, the corresponding y-value will be ...

  r = 2(-1-2) +1 = -6 +1

  r = -5

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

no one knows lol

step-by-step explanation: