6) The sum of three consecutive numbers is 120.
What is the smallest of the three numbers ?

39

Step-by-step explanation:

Let the smallest number be n,

then the three numbers are n, n+1 and n+2

Therefore, n+(n+1)+(n+2)=120

Collecting like terms,

n+n+n=120-1-2

3n=117

n=117/3

n=39

Therefore the numbers are 39,40 and 41.

And the smallest number is 39.

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

answer: f = 32.2m

step-by-step explanation: that is the answer