Task 2 Part 1. Create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. Use the equation below as a model. Use a constant in place of each variable a, b, c, and d. You can use positive and negative constants in your equation.

a(x+b)+c=d that has an extraneous solution

a(x+b)+c=d that does not have an extraneous solution

Part 3. Explain why the first equation has an extraneous solution and the second does not

part a)

for extraneous solution

1 ⋅ sqrt(x+2) + 3 = 0

for non extraneous solution

1⋅ sqrt(x+2)  + 3 = 6

part b) solve each equation

1⋅sqrt(x+2)+3=0

x+sqrt(x+2)=−3

square both sides

(sqrt(x+2))^ 2 = (−3)^2

x+2=9

x=9−2

x=7

do you see why its extraneous

Step-by-step explanation:

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.

the answer would be  

a.

3: 1

step-by-step explanation: