how many bricks each 22 cm long and 15 CM broad will be required to pave a court 30 metre long and 22 wide

20,000 bricks

Step-by-step explanation:

length of brick(L)=22cm

breadth of brick(B)=15cm

now,

area of brick(A)=L×B

=22×15s.q.cm

=0.033s.q.m

again,

length of court(l)=30m

breadth of court(b)=22m

now,

area of court(a)=l×b

=30×22s.q.m

=660s.q.m

lastly,

no.of required brick=area of court/area of

brick

=600 s.q.m/0.033s.q.m

=20,000bricks

the difference between a number and 5 is -2.

step-by-step explanation:

notice that the equation you are given has -2 (negative 2) on the right side, not 2. when you subtract 5 from a number n, you are finding the difference between the number and 5.

the difference between a number and 5 is -2.

you can use a^2+ b^2=c^2