HELP; Write the equation of a line that passes through the point (-16, -10) and is parallel to y = 5x+3

y = 5x + 70

Step-by-step explanation:

y = 5x + 3

For the new line to be parallel to this equation, the slope has to be the same.

y = 5x

The only thing that will change is the y-intercept. We know that the line has to pass the point (-16, -10).

y = 5x + 70

I Hope That This Helps! :)

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph