HELP ASAP An online auction charges sellers a flat fee of $1.20 and 2% of the amount of the sale. Let A be the amount of the sale in
dollars and C be the charge of the online auction. Explain whether the solutions A = -5 and C=1.1 are viable. (1 point)
O The solutions are not viable because the amount of the sale cannot be negative.
O The solutions are viable because the amount charged is positive.
O The solutions are not viable because the amount charged is not a whole number
O The solutions are viable because the amount of the sale is an integer.

The solutions are not viable because the amount of the sale cannot be negative.

Step-by-step explanation:

The solution A = -5 is not viable because A represents the amount of sale in dollars and so cannot be a negative number. The minimum amount that a person can make from sales is $0 so anything less than that is not viable.

For instance, if you are selling shoes for $4 each and make no sales in the day, your sales would be $0. It is not possible that your sales would be -$4.

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !