Find the circumcentre of A(0,0) B(3,5) and C(4,2).

ANSWER

Let A(4,6), B(0,4), C(6,2) be the vertices of the given △ABC.

Let P(x,y) be the circumcentre of △ABC. Then,

PA=PB=PC⟹PA

2

=PB

2

=PC

2

Now, PA

2

=PB

2

(x−4)

2

+(y−6)

2

=(x−0)

2

+(y−4)

2

x

2

+y

2

−8x−12y+52=x

2

+y

2

−8y+16

8x+4y=36

2x+y=9 (1)

Again, PB

2

=PC

2

(x−0)

2

+(y−4)

2

=(x−6)

2

+(y−2)

2

x

2

+y

2

−8y+16=x

2

+y

2

−12x−4y+40

12x−4y=24

3x−y=6 (2)

Solving equation 1 and 2, we get,

x=3,y=3

Therefore, the coordinates of circumcentre of △ABC are P(3,3).

Circumradius = PA=

(4−3)

2

+(6−3)

2

=

10

units

Hope it is helpful to you

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spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )