If an AaBbccDd individual is crossed to a AaBbCcDD individual, what is the probability that the first offspring will be of AabbccDd genotype?

The probability that the first offspring will be of AabbccDd genotype is 0.03125.

Step-by-step explanation:

The parents genotype are: AaBbccDd and AaBbCcDD.

         A           a

A      AA         Aa

a       Aa         aa

P (Aa) = 2/4 = 1/2

         B           b

B      BB         Bb

b      Bb         bb

P (bb) = 1/4

         c           c

C      Cc         Cc

c       cc         cc

P (cc) = 2/4 = 1/2

         D           d

D      DD        Dd

D      DD        Dd

P (Dd) = 2/4 = 1/2

Then the probability that the first offspring will be of AabbccDd genotype is:

P (AabbccDd) = (1/2) × (1/4) × (1/2) × (1/2) = 1/32

Thus, the probability that the first offspring will be of AabbccDd genotype is 0.03125.