Angle N = 40 degrees, side NP = 8, angle Q = 40 degrees, and side QS = 8. What additional information would you need to prove that ΔNOP ≅ ΔQRS by ASA?

<P ≅ <S

Step-by-step explanation:

Given: <N = , NP = 8,

           <Q = , QS = 8

Prove: ΔNOP ≅ ΔQRS by ASA

ASA implies Angle-Side-Angle; which is a congruent relation property of two triangles. This means that any two given triangles are congruent; if two angles and an included side are the same.

Since the side must be an included one (i.e between two given angles), then an additional information to prove that ΔNOP ≅ ΔQRS by ASA is;

<P ≅ <S

answer: -0.5 would be the most likley outcome

step-by-step explanation: