In a survey, of the voters support a particular referendum. If 40 voters are chosen at random, find the mean and variance for the number of voters who support the referendum.

This question is incomplete, the complete question is;

In a survey, 55% of the voters support a particular referendum. If 40 voters are chosen at random,

find the mean and variance for the number of voters who support the referendum.

a) The Mean is 22

b) Variance is 9.9

Step-by-step explanation:

Given that;

55% of the voters support a particular referendum p = 0.55

q = 1 - p = 1 - 0.55 = 0.45

sample size n = 40

a)

Mean = sample size n × p

Mean = 40 × 0.55

Mean = 22

Therefore the Mean is 22

b)

Variance = n × p × q

so we substitute

Variance = 40 × 0.55 × 0.45

Variance = 9.9

Therefore the Variance is 9.9

step-by-step explanation:

in which figure is point g a centroid

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.