When it is about 68°F, crickets chirp 124 times a minute. When it is about 80°F, they chirp 172 times a minute. WRITE an equation in POINT SLOPE FORM for the line that models this situation.

4x+148

Step-by-step explanation:

Let the temperature be x and time taken by cricket to chirp be y

if when it is about 68°F, crickets chirp 124 times a minute, this means;

at x1 = 68, y1 = 124

If it is about 80°F, they chirp 172 times a minute, then;

at x2 = 80, y2 = 172

The standard form of equation in point slope form is expressed as;

y-y0 = m(x-x0)

m is the slope

(x0, y0) is a point on the line.

First we need to get the slope.

m = y2-y1/x2-x1

m = 172-124/80-68

m = 48/12

m =4

Substitute m = 4 and any point into the expression above. Using the coordinate (68, 124)

get the intercept c

124 = 4(68) + c

c = 272-124

c = 148

The required equation is expressed as y = 4x+148 OR y - 124 = 4(x-68)

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204