$6,000 is invested in an account at interest rate r, compounded continuously. Find the time (in years) required for the amount to double when r= 9.5% and when r=2.5%.

When r= 9.5% , time = 7.3 years

When r= 2.5% , time = 27.7 years

Step-by-step explanation:

Exponential equation for compounded continuously:

, where P= Principal value invested , r= rate of interest, x= time

Given : P= $6,000

A = 2P= 2 ($6,000) = $12,000  (i)

When r= 9.5%= 0.095

 (ii)

From (i) and (ii)

For r= 2.5% = 0.025

part a

in a city ice cream is mostly only bought when the temperature is very high as ice cream cools down our

so we can derive the conclusion that as the temperature increases the number of ice creams sold also increases

part b

y intercept is 5

slope is 2

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42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

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