Approximately 1 in 28 people of Ashkenazi Jewish descent are Tay-Sachs carriers. In randomly sampling one man and one woman from this population, what is the probability neither is a Tay-Sachs carrier? What is the probability both are carriers?

a) probability that neither is Tay-Sachs carrier is 0.9298

b) the probability that both are carriers is 0.001276

Step-by-step explanation:

Given that;

1 in 28 people of Ashkenazi jewish descent are Tay-Sachs carrier.

so P(Carrier) = 1/28 =

also P( Not a carrier) = 1 - 1/28 = 0.9643

Now After Sampling 1 man and 1 woman from the population;

a)

the probability neither is Tay-Sachs carrier

P( Neither is a Carrier) = 27/28 × 27/28 = 0.9298

Therefore probability that neither is Tay-Sachs carrier is 0.9298

b)

the probability both are carriers

P( Both are Carriers) = 1/28 × 1/28 = 0.001276

Therefore the probability that both are carriers is 0.001276

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step-by-step explanation:

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