Mike wants to put 150 square feet of artificial turf in his front yard. This is the maximum area of artificial turf allowed by his homeowners association. He wants to have a rectangular area
of turf with length one foot less than 3 times the width. Find the length and width. Round to
the nearest tenth of a foot.

Step-by-step explanation:

Area of the rectangular area = Length * width

A = LW 1

If he wants to have a rectangular area  of turf with length one foot less than 3 times the width, then

L = 3W - 1 2

Substitute 2 into 1

A = (2W-1)W

A = 2W^2 - W

Since area = 150sq.ft

150 = 2W^2 - W

2W^2 - W - 150 = 0

Factorize

2W^2 - W - 150 = 0

W = 1±√1+4(300)/2(2)

W =  1±√1201/2(2)

W = 1±34.655/4

W = 35.655/4

W = 8.91375

W = 8.9 (to nearest tenth)

Get the length

L = A/W

L = 150/8.9

L = 16.85

L = 16.6ft

Hence the length is 16.6ft and the width is 8.9ft

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

b is the correct answer