State whether the triangles could be proven congruent, if possible, by SSS or SAS. Include a congruency statement for all congruent triangles.

The congruence theorems that can be used for each of the given pair of triangles are;

1) SSS

2) SAS

3)SAS

4) SSS

5) SAS

6) SAS

1) From the image we see that;

FY ≅ CW  

FP ≅ CM  

YP ≅ MW

This means that 3 corresponding sides of the 2 triangles are congruent and as such it means  ΔMCW ≅ ΔFPY using the Side-Side-Side (SSS) congruency theorem.

2) From the image we see that;

∠CBD and ∠BCA are both alternate interior angles and are therefore congruent. Thus;

∠CBD ≅ ∠BCA

Also, we see that;

EB ≅ EC

DB ≅ CA

This means that 2 corresponding sides and an angle of the 2 triangles are congruent and as such it means;

ΔBED ≅ ΔAEC using the Side-Angle-Side (SAS) congruency theorem.

3) From the image, we see that;

∠SVU ≅ ∠SVT

Using reflexive property, the shared sides give;

SV ≅ SV  

VT ≅ VU

This means that 2 corresponding sides and an angle of the 2 triangles are congruent and as such it means;

ΔVSU ≅ ΔVST using Side-Angle-Side (SAS) congruency theorem.

4) From the image, we see that;

MN ≅ QP

MQ ≅ NP

Using reflexive property, the shared sides give;

NQ ≅ NQ

This means that 3 corresponding sides of the 2 triangles are congruent and as such it means  ΔQNM ≅ ΔQNP using the Side-Side-Side (SSS) congruency theorem.  

5) From the image, we see that;

GL ≅ HL

GJ ≅ HK  

∠JLG and ∠HLK are vertically opposite angles and as such;

∠JLG ≅ ∠HLK

This means that 2 corresponding sides and an angle of the 2 triangles are congruent and as such it means;  

ΔQNM ≅ ΔQNP using Side-Angle-Side (SAS) congruency theorem.

6) We observe from the given triangles that;

∠XZY ≅ ∠XZW (They are both right angles = 90°)

Using reflexive property, the shared side is congruent to itself and so;

XZ ≅ XZ  

Also;

ZW ≅ ZY

This means that 2 corresponding sides and an angle of the 2 triangles are congruent and as such it means;  

ΔXYZ ≅ ΔXWZ  using Side-Angle-Side (SAS) congruency theorem.

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1. SSS

2. SAS

3. SAS

4. SSS

5. SAS

6. SAS

Step-by-step explanation:

1) Side FY ≅ Side CW  Given

Side FP ≅ Side CM     Given

Side YP ≅ Side MW    Given

∴ΔMCW ≅ ΔFPY by the Side-Side-Side (SSS) rule of congruency

2) ∠CBD ≅ ∠BCA given that both are alternate interior angles

Side EB ≅ Side EC and Side DB ≅ Side CA Given

ΔBED ≅ ΔAEC by Side-Angle-Side (SAS) rule of congruency

3. ∠SVU ≅ ∠SVT   Given

Side SV ≅ Side SV  by reflexive property

Side VT ≅ Side VU   Given

∴ ΔVSU ≅ ΔVST by Side-Angle-Side (SAS) rule of congruency

4. Side MN ≅ Side QP  Given

Side MQ ≅ Side NP     Given

Side NQ ≅ Side NQ    by reflexive property

∴ΔQNM ≅ ΔQNP by the Side-Side-Side (SSS) rule of congruency

5. Indirect proof

Side GL ≅ Side HL  Given

Side GJ ≅ Side HK     Given

∠JLG ≅ ∠HLK    vertically opposite angles

By sine rule

GJ/sin(∠JLG) = GL/n(∠GJL)

Similarly

HK/sin(∠HLK) = HL/n(∠HKL)

∴ ∠GJL ≅ ∠HKL

∴ ∠LGJ ≅ ∠LHK third angle of two triangles given the other two angles are congruent

∴ΔQNM ≅ ΔQNP by the Side-Angle-Side (SAS) rule of congruency

6. ∠XZY ≅ ∠XZW   Supplementary ∠s with ∠XZY = 90°

Side XZ ≅ Side XZ  by reflexive property

Side ZW ≅ Side ZY   Given

∴ ΔXYZ ≅ ΔXWZ by Side-Angle-Side (SAS) rule of congruency.

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

ddd

step-by-step explanation: