Help

please give sensible answer :(

(6) QP = QR therefore, triangle QPR is an isosceles triangle.

Since QPR is an isosceles triangle, the base angles are equal.

angle P + angle R + 80 = 180

2x + 80 = 180

2x = 100

x = 50.

That is just the measure of the base angle.

Now take triangle TSR.

Since R = 50, due to angle sum property, we can come up with this equation:

50 + 85 + x = 180

x = 180 - 135

x = 45 <- That's the answer.

(8) Take triangle PSQ, you get angle P = 70 degrees using the angle sum property and algebra.

Now take triangle PSR and you get angle P in the triangle as (180 - 100) / 2 = 40.

Since P = 70, and P in the smaller triangle is 40, 70 - 40 would be the answer.

x = 30 degrees <- That's the answer :D

a is the correct