Carlos performed a transformation on trapezoid EFGH to create E′F′G′H′, as shown in the figure below: Image Description: A four quadrant coordinate grid is drawn. Trapezoid EFGH with coordinates are drawn at E negative 6, negative 4. F is at negative 4, negative 4. G is at negative 2, negative 6. H is at negative 7, negative 7. Trapezoid E prime F prime G prime H prime with coordinates are drawn at E prime negative 4, 6. F prime is at negative 4, 4. G prime is at negative 6, 2. H prime is at negative 7, 7.

What transformation did Carlos perform to create E′F′G′H′?

Options:
A. Rotation of 270° clockwise about the origin
B. Reflection across the x-axis
C. Rotation of 90° clockwise about the origin
D. Reflection across the line of symmetry of the figure

The correct option is;

C. Rotation of 90° clockwise about the origin

Step-by-step explanation:

The given coordinates of the trapezoid EFGH are;

E(-6, -4) F(-4, -4), G(-2, -6), H(-7, -7)

The given coordinates of the trapezoid E'F'G'H' are;

E'(-4, 6) F'(-4, 4), G'(-6, 2), H(-7, 7)

We observe that the given transformation of trapezoid EFGH to trapezoid E'F'G'H' is given as follows;

Preimage coordinate = (x, y), Image coordinate = (y, -x) after the transformation, which is equivalent to a 90° clockwise rotation

The transformation that involves a rotation of 90° clockwise about the origin is given as follows;

The coordinate of a point of the preimage = (x, y)

The coordinate of a point of the image after the rotation = (y, -x)

it's C

Step-by-step explanation:

got it right on the test

u dumb boi

step-by-step explanation: