A population of values has a normal distribution with μ=152.8 and σ=26.2 . You intend to draw a random sample of size n=94 . Find the probability that a single randomly selected value is less than 149.6.
P(X < 149.6) =

P = 0.022

Step-by-step explanation:

Draw a normal distribution curve

Find the z score.

z score = 0.12

Find the probability for the z score.

P = 0.478

Subtract probability from 0.5

0.5 - 0.478 =0.022

the answer is (-4,-4)

hope this ! : d

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v