Solve for z.
12 = 15(z-1/5

z=  1

Step-by-step explanation:

Rewrite the equation as  

15(z−1/5)z12

Apply the distributive property

15z+15(−1/5)=  12

Cancel the common factor of  5

15z+3*−1=  12

Multiply  3  by  −1

15z−3=  12

Divide each term by  15  and simplify

5z−1  =  4

Since the expression on each side of the equation has the same denominator, the numerators must be equal

5z−1=  4

Move all terms not containing  z  to the right side of the equation

5z=  5

Divide each term by  5  and simplify

z  =  1

160

step-by-step explanation:

idk

i hope i

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.