Among at most how many coins can you find the “light one” if you are permitted to use the scale only twice? Only three times?

So in two weighings, we can find a single light coin from a set of 3 × 3 = 9. By extension, it would take only three weighings to find the odd light coin among 27 coins, and four weighings to find it from 81 coins.

Step-by-step explanation:

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it