Find the error in the calculations below, if there is one:

Between line 1 and 2

Step-by-step explanation:

4x³ +2x²- 6x+ 3     (Line 1)

note that +3 can be written as  -(-3), giving us:

4x³ +2x² -6x - (-3)

if we group the first two terms and the last two terms, we will get

(4x³ +2x²) + [ -6x - (-3) ]   (factor out 2x from first group and -3 from second group)  

= 2x²(2x +1) -3(2x - 1 )

if we compare this with (Line2) we can see that the difference is in the sign of the last term inside the second group. Hence this is where the mistake is made Between line 1 and 2

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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