Someone pleaseee help
(middle school math)
photo math isn't helping me rn lol

x≤−9 or x≥5 or x=0

Step-by-step explanation:

Let's solve your inequality step-by-step.

x2(x+9)(x−5)≥0

x4+4x3−45x2≥0

Let's find the critical points of the inequality.

x4+4x3−45x2=0

x2(x−5)(x+9)=0(Factor left side of equation)

x2=0 or x−5=0 or x+9=0(Set factors equal to 0)

x=0 or x=5 or x=−9

Check intervals in between critical points. (Test values in the intervals to see if they work.)

x≤−9(Works in original inequality)

−9≤x≤0(Doesn't work in original inequality)

0≤x≤5(Doesn't work in original inequality)

x≥5(Works in original inequality)

x≤−9 or x≥5 or x=0

I also recommend MathPapa or Symbolab to help you with your math.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2