Solve the system of equations below for a, b, and c. 2a + b - 2c = -7
6a + 3b - c = -26
4a + 2b + 2c = -20

Please answer quick!!! I appreciate ANY help

a=-1/2b+c+-7/2

a= -1/2b+1/6c+-13/3

a= -1/2b+-1/2c-5

I really hope that my answer is right

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752