In a survey of a random sample of 35 households in the Cherry Creek neighborhood of Denver, it was found that 8 households turned out the lights and pretended not to be home on Halloween. Compute a 90% confidence interval for p, the proportion of all households in Cherry Creek that pretend not to be home on Halloween. (Round your answers to four decimal places.)

(0.1118, 0.3454)

Step-by-step explanation:

Confidence interval for population proportion is given by :-

, where = sample proportion , n= sample size, = critical z-value for c confidence level.

Let p = the proportion of all households in Cherry Creek that pretend not to be home on Halloween.

Given : n= 35

Critical z-value for 90% confidence level =1.645

A 90% confidence interval for p, the proportion of all households in Cherry Creek that pretend not to be home on Halloween:

∴ Required confidence interval : (0.1118, 0.3454)

astronomers is your final answer! : )

14.29%

step-by-step explanation: