How far will 25 N of force stretch a spring with a spring with a spring constant of 125 N/m?

-0.656168ft

Step-by-step explanation:

If Spring force constant (k)  is 125  N/m

And the force is (F) 25 N ,

then the spring displacement (Δx) -0.656168

Equation used:

Knowing Hooke's law, we can write it down it the form of a formula:

F = -kΔx

F is the spring force (in N);

k is the spring constant (in N/m); and

Δx is the displacement (positive for elongation and negative for compression, in m).

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i