On paper, draw a diagram to model the following problem. Solve and enter your answer in the box. The area of the rectangular binder cover is 80 square inches. It has an area that is 8 times the area of the rectangular spiral notebook cover. If the length of the spiral notebook is 5 inches, what is its perimeter?

The perimeter of the spiral notebook is 14 inches

Step-by-step explanation:

The given parameters are;

The area of the rectangular binder cover, Aₓ = 80 in²

The area of the rectangular binder cover = 8 × The area of the spiral notebook, Aₙ

The length, l of the spiral notebook = 5 inches

Let w represent the width of the spiral notebook cover;

We have;

Aₙ = l × w = 5 × w

Aₓ = 80 = 8 × Aₙ

8 × Aₙ = 80

∴ 8 × 5 × w = 80

w = 80/(8 × 5) = 80/40 = 2

w - 2 inches

The perimeter, P, of a rectangle = 2 × length, l + 2 × width, w

∴ For the spiral notebook, we have,  = 2 × 5 + 2 × 2 = 14

The perimeter of the spiral notebook, = 14 inches.

add -60 to 120 which will result in : 2x+3y=180

then subtract 2x: 3y=-2x+180

lastly, divide by 2: y= -2/3x+60

hope this is the answer you're looking for: )