A dog is pulling a 15kg sled to the right with a force of 15N. A rhino is pulling the same sled to the left with a force of 42N. There is a frictional force of 5.0N acting on the sled. Which direction is the friction acting?

What is the Net Force on the sled?

What is the acceleration of the sled?

What is the coefficient of friction on the sled?

9514 1404 393

Step-by-step explanation:

a) Friction opposes motion, so is in the opposite direction of the net force on the sled. Taking "left" to be "positive", the two animals are applying a net force of +42 N -15 N = 27 N. That is to the left, so the friction force is to the right.

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b) The total of forces applied by the animals and friction is ...

  27 N -5 N = 22 N . . . to the left

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c) Acceleration can be found from the relation ...

  a = F/m . . . . 'm' is mass

  a = (22 N)/(15 kg) = 22/15 m/s² . . . . 'm' is meters

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d) The coefficient of friction is the ratio of friction force to the normal force on the surface producing the friction. Here, that normal force is the force due to gravity acting on the 15 kg mass of the sled.

 coefficient of friction = (5 N)/(9.8 m/s²·15 kg) = 5/147

 coefficient of friction ≈ 0.034

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi

a

step-by-step explanation:

strong negative correlation