V'W'X'Y' has vertices V^' (-3,2),W^' (5,1),X^' (0,4),and Y'(-2,0). If V'W'X'Y' is the image of VWXY rotated 90° around the origin. What are the coordinates of VWXY (the pre-image).

Given:

V'W'X'Y' has vertices V'(-3,2), W'(5,1), X'(0,4) and Y'(-2,0).

V'W'X'Y' is the image of VWXY rotated 90° around the origin.

To find:

The coordinates of VWXY (the pre-image).

Solution:

V'W'X'Y' is the image of VWXY rotated 90° around the origin. It means, the figure VWXY is rotated 90° counterclockwise around the origin.

So, if we rotate V'W'X'Y' 90° clockwise around the origin, then we get the original figure VWXY.

If a figure rotated 90° clockwise around the origin, then

Therefore, the coordinates of preimage are V(2,3), W(1,-5), X(4,0) and Y(0,2).

o= 4(i) +3

step-by-step explanation:

o is your output value and i is your input value. so, for example, if we stuck 7 in as our input, we would first multiply by 4 ( pemdas ), which equals 28. then we would add 3 to 28, for a total output of 31. this may not be a graph, but, it is a way to solve your formula..

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.