Please help me if you know how to do this

Question 17

Explanation:

We know that a = 1 so it matches with the 'a' value in y = x^2. Otherwise, the shapes wouldn't match up and they wouldn't be congruent.

The vertex we want is (h,k) = (2,-3)

Therefore,

y = a(x-h)^2 + k

y = 1(x-2)^2 + (-3)

y = (x-2)^2 - 3

Question 18

Explanation:

The equation y = 3(x-1)^2 - 4 is in the form y = a(x-h)^2 + k which is known as vertex form.

a = 3 being positive tells us the graph opens upward and we have a min point. There is no max point as it goes on forever upward.

The min point is k = -4 which is the y coordinate of the vertex.

Question 19

Explanation:

The equation opens up, so the value of 'a' must be positive. This narrows our choices to A or B.

We eliminate choice A because that graph is more narrow compared to y = x^2. Choice B is wider and flatter compared to y = x^2 due to 1/2 being smaller than 1.