WILL BRAINLIEST IF ANSWERED UNDER 3 MINUTES! A football team has an away game, and the bus breaks down. The coaches decide to drive the players to the game in cars and vans. Four players can ride in each car. Six players can ride in each van. There are 48 players on a team. The equation 4x + 6y = 48 models this situation, where x is the number of cars and y is the number of vans.

Find 4 possible solutions in the context of the problem.

Answers:

(0, 8)

(3, 6)

(6, 4)

(12, 0)

There are infinitely many answers to pick from. All that matters is that they are on the line 4x+6y = 48

Explanation:

Plug in x = 0 and solve for y to get y = 8. That means we can have 0 cars and 8 vans.

Plug in y = 0 and solve for x to get x = 12. So we could have 12 cars and 0 vans.

That takes care of two possible solutions, but we need 2 more.

Here's how to get more solutions. Start at the point (0,8). Then we'll use the slope to help get to another point. The slope here is -4/6 = -2/3, so we go down 2 and over to the right 3.

Starting at (0,8) and going down 2 and to the right 3 has us land on (3,6) which is another solution. I'll let you confirm if (x,y) = (3,6) works in the equation or not. This solution tells us we could have 3 cars and 6 vans.

Then from (3,6) we do another "down 2, right 3" motion to land on (6,4) which is yet another solution. In this case, we have 6 cars and 4 vans.

We can stop here since we have four solutions now.

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