Ramen noodles. There are 20 ramen noodle packages in a bag. There are 10 beef flavored, and the other 10 are chicken flavored. What is the probability of getting at least one chicken and at least one beef flavor when you grab 3 packages randomly?

0.789

Step-by-step explanation:

Number of beef flavored Ramen noodles = 10

Number of chicken flavored Ramen noodles = 10

Total number of noodles = 20

Number of ways to select 3 packages:

Number of ways to select two beef flavored Ramen noodle = = 45

Number of ways to select one chicken flavored Ramen noodle = 10

Number of ways to select two chicken flavored Ramen noodle = = 45

Number of ways to select one chicken flavored Ramen noodle = 10

Total number of ways so that one chicken and one beef Ramen selected = 450 + 450 = 900

Formula for probability of an event E can be observed as:

Required probability is:

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12