Review the proof of sin(A β B) = sinAcosB β cosAsinB
sin(A β B) =
Step 1: Equals cosin...
Mathematics, 05.11.2020 17:40, efritzke
Review the proof of sin(A β B) = sinAcosB β cosAsinB
sin(A β B) =
Step 1: Equals cosine left-bracket (StartFraction pi Over 2 EndFraction minus A) + B right-bracket
Step 2: Equals cosine left-bracket StartFraction pi Over 2 EndFraction minus (A minus B) right-bracket
Step 3: Equals cosine (StartFraction pi Over 2 EndFraction minus A) cosine B minus sine (StartFraction pi Over 2 EndFraction minus A) sine B
Step 4: = sinAcosB β cosAsinB
How must the proof be rearranged for the steps to logically follow each other?
a. Step 3 should be step 1.
b. Step 4 should be step 1.
c. Steps 1 and 2 must be switched.
d. Steps 1 and 3 must be switched.
Answers: 1
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